Forum Discussion
Jason Hopp
Mar 24, 2017Brass Contributor
How to remove the Welcome Message when a new member joins a group.
We are moving from an on-premise Exchange 2013 environment (using Hybrid) and we have to move our DLs to the cloud. I can create them through powershell as a distribution group, but that does not wr...
- Mar 28, 2017
You can use the following command to suppress the welcome message for any new users added to the group as a member. The default value will be set to true for this parameter. So you will need to pass "false" as the value to suppress the welcome message.
Set-UnifiedGroup <groupname> -UnifiedGroupWelcomeMessageEnabled:$<true/false>
VasilMichev
Mar 24, 2017MVP
I'm not aware of any method to bypass the message. cfiessinger might be able to help or take some feedback on this.
- Siva ShanmugamMar 28, 2017
Microsoft
You can use the following command to suppress the welcome message for any new users added to the group as a member. The default value will be set to true for this parameter. So you will need to pass "false" as the value to suppress the welcome message.
Set-UnifiedGroup <groupname> -UnifiedGroupWelcomeMessageEnabled:$<true/false>
- arvinthgSep 12, 2022Copper ContributorHi, is there a way to disable this property through Graph API?
- Nicholas_RogersNov 29, 2021Copper Contributor
Can I switch off Welcome Messages in a Private ordinary FB Group?? There is nowhere that I can insert or modify code that I am currently aware of. Sorry that it is such a mundane question.
- gellionhJun 07, 2021Copper Contributor
Siva Shanmugam Hi, I don't know where to enter thiscommande, and am afraid it wouldbe accessible only to some kind of Teams admins. Is that right? else can you provide some additional guidance pls?
- mgudites1Jun 07, 2021Brass Contributor
gellionh You have to open an Exchange Online Powershell window and run that command in it. Although this issue is happening when you add users to a Team/SharePoint site, it's the Exchange "Group" that's attached to the Team where this setting actually exists.